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← Revision 5 as of 2013-03-08 10:17:15 ⇥
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Power for a two-tailed one sample binomial test
For testing the (two-tailed) hypothesis that a sample of size, ntot, with proportion, prop, equals a constant, const, with a type I error of alpha copy and paste the below into R and adjust inputs as required:
prop <- 0.45 const <- 0.50 ntot <- 900 alpha <- 0.05
Then copy and paste the below into R. Pow is the power of the test.
chisq <- ( (prop-const)^2 ) / (const*(1-const)) chisq <- ntot*chisq pow <- 1 - pchisq(abs(qchisq(1-alpha,1)),1,chisq) print(pow)
