Diff for "FAQ/perc" - CBU statistics Wiki
location: Diff for "FAQ/perc"
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Revision 1 as of 2008-04-11 10:52:14
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Editor: PeterWatson
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Revision 21 as of 2013-03-08 10:17:13
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Editor: localhost
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Percentile (score) = 100$$\frac{n \leq score}{N}$$ Percentile (score) = 100 $$\frac{\mbox{n} \leq \mbox{score}}{\mbox{N}}$$
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1 - Percentile (score) = 100$$\frac{n \gt score}{N}$$ 100 - Percentile (score) = 100 $$\frac{\mbox{n} \gt \mbox{score}}{\mbox{N}}$$
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The percentiles for each score are routinely outputted using the frequency procedure in SPSS. The score percentiles can be obtained by running the below in SPSS.
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or the below in R:

{{{
score <- sort(score)
perc <- rep(-99,length(score))
ict <- 1
b <- duplicated(score)
for (ict in 1:length(score) {
for (i in score) {
perc[ict] <- 100*sum(score<=i)/length(score)
ict <- ict+1
}
 }
(percu <- perc[!duplicated(perc)])
(scoreu <- score[!duplicated(score)])
percu
scoreu
}}}

How do I find out how many people have a score above a certain value?

Percentiles give the percentage of people who have a score below a threshold score.

Percentile (score) = 100 $$\frac{\mbox{n} \leq \mbox{score}}{\mbox{N}}$$

100 - Percentile (score) = 100 $$\frac{\mbox{n} \gt \mbox{score}}{\mbox{N}}$$

The score percentiles can be obtained by running the below in SPSS.

FREQUENCIES VAR=SCORE.
EXE.

or the below in R:

score <- sort(score)
perc <- rep(-99,length(score))
ict <- 1
b <- duplicated(score)
for (ict in 1:length(score) {
for (i in score) {
perc[ict] <- 100*sum(score<=i)/length(score)
ict <- ict+1
}
 }
(percu <- perc[!duplicated(perc)])
(scoreu <- score[!duplicated(score)])
percu
scoreu

None: FAQ/perc (last edited 2013-03-08 10:17:13 by localhost)