<?xml version="1.0" encoding="utf-8"?><!DOCTYPE article  PUBLIC '-//OASIS//DTD DocBook XML V4.4//EN'  'http://www.docbook.org/xml/4.4/docbookx.dtd'><article><articleinfo><title>FAQ/power/powexampleN</title><revhistory><revision><revnumber>22</revnumber><date>2013-03-08 10:17:38</date><authorinitials>localhost</authorinitials><revremark>converted to 1.6 markup</revremark></revision><revision><revnumber>21</revnumber><date>2008-09-25 09:21:02</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>20</revnumber><date>2008-09-25 09:19:53</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>19</revnumber><date>2008-09-25 09:16:48</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>18</revnumber><date>2008-09-25 09:11:39</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>17</revnumber><date>2008-09-24 16:26:09</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>16</revnumber><date>2008-09-24 16:15:12</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>15</revnumber><date>2007-09-05 10:18:23</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>14</revnumber><date>2007-09-05 10:16:21</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>13</revnumber><date>2007-09-05 10:13:23</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>12</revnumber><date>2007-09-05 09:47:36</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>11</revnumber><date>2007-09-05 09:46:08</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>10</revnumber><date>2007-09-05 09:45:31</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>9</revnumber><date>2007-09-05 09:42:40</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>8</revnumber><date>2007-09-05 09:39:38</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>7</revnumber><date>2007-09-05 09:37:55</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>6</revnumber><date>2007-09-05 09:35:28</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>5</revnumber><date>2007-09-05 09:33:31</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>4</revnumber><date>2007-09-05 09:23:10</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>3</revnumber><date>2007-06-11 15:51:44</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>2</revnumber><date>2007-06-11 15:49:54</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>1</revnumber><date>2007-03-20 15:13:49</date><authorinitials>PeterWatson</authorinitials></revision></revhistory></articleinfo><para>Suppose we have a three way interaction of three factors called age, sex and type. Age and sex have two levels and are between subject and type has four levels and is within subject.  </para><para>Pilot data has suggested an effect size, partial eta-squared, of 0.10 as worthy of interest. We wish to do a power calculation to see the power to detect an eta-squared of at least 0.10 with a total sample size of 20 and a Type I error of 5%.  </para><para>There are two between subjects factors (age, sex) each with 2 levels so the df for both age and sex equals (2-1)=1. Their interaction (which makes up the term of interest) has a df of (2-1)*(2-1)=1. There is one within subject factor (type) with 4 levels so the df for type is (4-1)=3. We can now use these to work out our inputs.  </para><para>num = numerator df of age by sex by type interaction = (2-1)(2-1)(4-1)= 3  </para><para>bsum = (2-1) + (2-1) + (2-1)*(2-1) = 3  (sum of dfs for between subject factor terms: age, sex and age*sex interaction) </para><para>wdf = (4-1) = 3 (df for the within subject factor type) </para><para>Now putting these together, taking the conservative assumption that the types are uncorrelated, an alpha of 0.05, partial eta-squared of 0.10 and a total sample size of 20 gives a power of 0.43.  </para><para>If we assume that the average correlation between a pair of  types is 0.25 then an alpha of 0.05, partial eta-squared of 0.10 and a total sample size of 20 has a power of 0.56. </para><para><emphasis role="underline">Reference</emphasis> </para><para>Faul, F. &amp; Erdfelder, E. (1992) GPOWER: A priori, post-hoc, and compromise power analyses for MS-DOS [Computer program]. Bonn, Germany: Bonn University, Dep. of Psychology.   </para></article>